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8b^2+b-7=0
a = 8; b = 1; c = -7;
Δ = b2-4ac
Δ = 12-4·8·(-7)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-15}{2*8}=\frac{-16}{16} =-1 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+15}{2*8}=\frac{14}{16} =7/8 $
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